-4m^2-47+8m=8m+2-5m^2

Solution for -4m^2-47+8m=8m+2-5m^2 equation:

-4m^2-47+8m=8m+2-5m^2

We move all terms to the left:

-4m^2-47+8m-(8m+2-5m^2)=0

We get rid of parentheses

-4m^2+5m^2-8m+8m-2-47=0

We add all the numbers together, and all the variables

m^2-49=0

a = 1; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·1·(-49)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*1}=\frac{-14}{2}
=-7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*1}=\frac{14}{2}
=7
$